57=(2x)^2/(.1-x)(.2-x)

Solution for 57=(2x)^2/(.1-x)(.2-x) equation:

57=(2x)^2/(.1-x)(.2-x)

We move all terms to the left:

57-((2x)^2/(.1-x)(.2-x))=0


Domain of the equation: (.1-x)(.2-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(.2-x)!=-.1

x∈R


We add all the numbers together, and all the variables

-(2x^2/(-1x+0.1)(-1x+0.2))+57=0

We multiply parentheses ..

-(2x^2/(+x^2-0.2x-0.1x+0.02))+57=0

We multiply all the terms by the denominator


-(2x^2+57*(+x^2-0.2x-0.1x+0.02))=0


We calculate terms in parentheses: -(2x^2+57*(+x^2-0.2x-0.1x+0.02)), so:

2x^2+57*(+x^2-0.2x-0.1x+0.02)

We multiply parentheses

2x^2+57x^2+0x+0x+1.14

We add all the numbers together, and all the variables

59x^2+2x+1.14

Back to the equation:

-(59x^2+2x+1.14)


We get rid of parentheses

-59x^2-2x-1.14=0

a = -59; b = -2; c = -1.14;
Δ = b2-4ac
Δ = -22-4·(-59)·(-1.14)
Δ = -265.04
Delta is less than zero, so there is no solution for the equation